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Mathematics 15 Online
OpenStudy (anonymous):

4x^2+1 is greater than or equal to 4x

OpenStudy (anonymous):

\[4x ^{2}+1 \ge 4x\]

OpenStudy (anonymous):

What is your question @emmyvirkus?

OpenStudy (anonymous):

I need to express the solution in interval notation

OpenStudy (anonymous):

solution set***

OpenStudy (anonymous):

OK, so interval notation, not to be confused with a coordinate on the Cartesian coordinate plane will look like (x, y) or [x, y) or (x, y] etc. Where we use brackets to say we are including the point's and parentheses when we are not including the points. Are you with me so far?

OpenStudy (anonymous):

Yes I understand that part :)

OpenStudy (anonymous):

Let's make this simpler.

OpenStudy (anonymous):

yes i'm with you!

OpenStudy (anonymous):

4x^2 - 4x [>/=] -1 We can arrive at this by moving around our terms. |dw:1405200827685:dw|

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