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with the integral of x/(1-x^2)^3 use u substitution to find what it is, i get the answer but it is reverse the fraction should be on top but its on the bottom, please help the answer it 1/[4(1-x^2)^2] and i get the reverse of that
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Let's see.|dw:1405201018672:dw|
What did you use as your substitution ?
Is that what you got?
+ C
You mean 1/(4(1-x^2)^2), right anteater?
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Yes :)
That's what I got as well.
i got that reverse for some reason , i thought that du would be on top and u would be on bottom
It is. You can use 1 - x^2 as your u. Then du = -2x dx. So since you have x dx, that is -1/2 du
And then you have that over u^3
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Hope that helps! Anteater gotta go :)
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