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OpenStudy (anonymous):
x^(x+6)=x^(4x-3)
I got x=3, but there is another answer: x=1
why and how do I reach it?
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OpenStudy (sheraz12345):
it should be 3 i guess
jhonyy9 (jhonyy9):
so how do you think 1 on indifferent exponent how many will be ?
jhonyy9 (jhonyy9):
hope yo know that 1 on indifferent exponent will be 1
yes ?
OpenStudy (anonymous):
That's a good point jhonyy, perhaps my example wasn't good enough, here is another one:
(x-3)^(x-3)=(x-3)^(4-x)
OpenStudy (anonymous):
Again I get 3.5, but there is also 4
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jhonyy9 (jhonyy9):
but for the first exercise the 3 is right too
than you just need make try calcule it and see that will add the same answer
jhonyy9 (jhonyy9):
for the second you see that the base so in this case (x-3) is equale in other sides
so than just you need make the exponents equales
ok ?
OpenStudy (anonymous):
i have to make them equal to 1?
jhonyy9 (jhonyy9):
why 1 ?
OpenStudy (anonymous):
(x-3), if x is 4, then the base is 1 and therefore 1 to any power is 1
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OpenStudy (anonymous):
(x-3)^(x-3)=(x-3)^(4-x) => x=4
(4-3)^(4-3)=(4-3)^(4-4)
1^1=1^0
1=1
jhonyy9 (jhonyy9):
yes 4 is right
OpenStudy (anonymous):
I see
jhonyy9 (jhonyy9):
hope you understand it now sure
OpenStudy (anonymous):
Yeah thanks man
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jhonyy9 (jhonyy9):
my pleasure
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