x^(x+6)=x^(4x-3) I got x=3, but there is another answer: x=1 why and how do I reach it?
it should be 3 i guess
so how do you think 1 on indifferent exponent how many will be ?
hope yo know that 1 on indifferent exponent will be 1 yes ?
That's a good point jhonyy, perhaps my example wasn't good enough, here is another one: (x-3)^(x-3)=(x-3)^(4-x)
Again I get 3.5, but there is also 4
but for the first exercise the 3 is right too than you just need make try calcule it and see that will add the same answer
for the second you see that the base so in this case (x-3) is equale in other sides so than just you need make the exponents equales ok ?
i have to make them equal to 1?
why 1 ?
(x-3), if x is 4, then the base is 1 and therefore 1 to any power is 1
(x-3)^(x-3)=(x-3)^(4-x) => x=4 (4-3)^(4-3)=(4-3)^(4-4) 1^1=1^0 1=1
yes 4 is right
I see
hope you understand it now sure
Yeah thanks man
my pleasure
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