What's the most parallel as possible line we can make to the side of the parabola y=x^2 from x=0 to x=infinity?

Question

zzr0ck3r · Answer

what?

kainui · Answer

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zzr0ck3r · Answer

you need to pick a point for it to be parallel to, then its the tangent line.

kainui · Answer

I want it to be most close to being average to the slope at every point.

zzr0ck3r · Answer

there is parallel and not parallel, there is nothing inbetween

zzr0ck3r · Answer

my guess is that would be at 0

zzr0ck3r · Answer

no idea ... lol

kainui · Answer

Well the slope is different at every point on y=x^2. I want to make the difference between the slope on a line to be as close as possible to the slope at every point. Since the slope only gets more and more positive the further to the right you go, I think a fairly safe first guess is a slope of 1 if that makes sense.

zzr0ck3r · Answer

but x^2 is always changing, so I dont see how you would compute this "average".

zzr0ck3r · Answer

ill stay posted to see what others do. interesting:)

anonymous · Answer

It almost sounds like needing to take the limit of the derivative of y=x^2 ... But that would just be infinity... So maybe make a table of several large numbered x values with their instantaneous slopes and finding a slope that they appear to be approaching?

But avoiding all the math, my best guess would be a slope of m=infinity

anonymous · Answer

If x is infinity and the function is y=x^2 it will never converge, it has no limit, it is divergent. Or u might even say that the slope is undefined because the slope from one point to the next essentially would become vertical.

anonymous · Answer

draw a slope graph and find the distance vertically