Question

What are the factors of 3x2 + 23x − 8

Answer 1

It is multiple choice

Answer 2

(3x − 4)(x + 2)
(3x − 2)(x + 4)
(3x − 8)(x + 1)
(3x − 1)(x + 8)

Answer 3

Ok so we just need to factor this. Let's work out which one works to give us the polynomial 3x^2+23x-8

Let's try the first one.

After distributing we get
3x^2 + 6x - 4x - 8 or
3x^2 + 2x -8

Which is not 3x^2+23x-8

So we can rule out A

Answer 4

ok so i can just do that

Answer 5

Do the same with the other 3.

Multiply them out using FOIL, and see which one comes out to give you 3x^2+23x-8

Answer 6

@lacrosseplayer22 is Correct. It will be the last on the list. But do you know why?

Answer 7

The last one on the list is (3x-1)(x+8)

When we distribute, we get 3x^2+23x-8
Which is what you started with so therefore is the correct answer.

(3x-1)(x+8) are the factors of 3x^2+23x-8

Answer 8

sorry guys. I just factored in my head a knew it was the last one. there is an actual way to do it. don't follow my way. that was stupid

Answer 9

yeah he used the distrubitive property

Answer 10

Thanks for your both of your help