Question

I solved a system of equations and the result was that it canceled out and i was left with just a number on the other side of the equal sign. Does that mean the answer is no solution or infinite solutions?

Answer 1

@phi

Answer 2

@zepdrix

Answer 3

can i see the 2 equations

Answer 4

and if you get 0=0, does that mean no solution? or all real numbers (infinite solutions)

Answer 5

Chances are, yes, if you end up with 4=9, or 0=5.
Just to be sure, you may want to post the system of (how many) equations so that someone can help you check if it was a mistake somewhere.

Answer 6

yeah if the equalsign makes sense.. then infinite or else no solution

Answer 7

alright! 3x+3y-7z=-2
4x+y-3z=8
-16x+5y-7z=-5

Answer 8

those are the three equations, i get 36x-8z=104
-36x+8z=-45 at the end. and it cancels. you see what i mean?

Answer 9

if it cancels to say, 4=5 then there is no solution but if it is like 0=0 it is always true and an identity meaning infinite

Answer 10

well what if its like 0=56

Answer 11

does 0 ever =56?

Answer 12

noooooo

Answer 13

exactly so it is never

Answer 14

;) I'm just a tard. thank you

Answer 15

36x-8z=104
-36x+8z=-45

Assuming the two equations you got are correct,
36x-8z=104
-36x+8z=-45

They can never be true for any value of x and y.

Answer 16

Geometrically these two equations:
36x-8z=104
-36x+8z=-45
indicate two parallel lines with different y-intercepts.
They are parallel and non-coinciding, so no solution.

Answer 17

thank you guys!!!

Answer 18

You're welcome! :)