A system of linear inequalities is shown below. x - y > 3 y + x ≤ 2 Describe the steps to graph the solution set to the system of inequalities. (10 points)
Okay yes I was correct sorry I doubted myself there.. You want to solve the equations for y
?
x-y>3 -y>3-x y<x-3
y</=-x+2
Well you need to solve first ik that
but it says to graph it
like the steps >.<
They want it graphed on coordinate plane correct?
yes i think so... i dont know... can you show me both?
just in case
Yes I can show you y<x-3 look at it like an equation in slope-intercept form. Since there is nothing infront of the x it is a slope of 1 and it has a y intercept of -3. But you don't graph this one like a normal line, since it is not less than or equal to you must graph a dashed line
oh ok...
but there is more you have to do too, after you have graphed both of them
It says to show steps though...
Oh okay what you do is you go on the y axis, count down 3 units, go up 1 and over 1 then draw a dashed line through them and lightly shade underneath the line
The shading i the solution to the first inequality, where the shading overlaps is the solution of the set
oh o and what about graphing on a number line?
I forgot how to graph them on a number line it has been so long... can anyone else help ?
lol
its ok
isnt it closed or open circle and a bunch of shading?
Yes I know that but we still have x in our inequalities
@IMStuck
closed circle is for less than or equal to/greater than or equal to. open circle is just for less than or greater than
thank you guyz!
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