Question

Chemistry doubt?????

Answer 1

this is the math section though...

Answer 2

@Kainui Ask him about chem :)

Answer 3

A balloon containing 1 mole air at 1 atm initiallyis filled further with air till pressure increases to 4 atm. The initial diameter of the ballon is 1m and the pressure at each stage is proportion to diameter of the balloon. How many moles of air are needed to change the pressure to 4atm

Answer 4

@iambatman hlp

Answer 5

@goformit100 not a spam

Answer 6

SPAM^

Answer 7

yeah

Answer 8

p1vi/n1=p2v2/n2

Answer 9

r_2^3=1/32

Answer 10

Post Question in correct section

Answer 11

but there are not many people in chemistry section

Answer 12

@Kainui hlp a chemistry question

Answer 13

So You are SPAMMING Simply Sir.

Answer 14

\[\frac{ P_1V_i }{ n_1 }=\frac{ P_2V_f }{ n_2}\]?

Answer 15

yes i used the same

Answer 16

check the answer @Johnbc

Answer 17

Diameter of balloon is proportional to the pressure at each stage.
\[D \alpha P_F\]\[Dk=P_f\]

Answer 18

yes

Answer 19

\[V = \frac{ 4 }{ 3 } \pi r^2\]
Diameter = 2radius
Radius = Diameter/2

Answer 20

yes

Answer 21

Sir, Please Close the question.

Answer 22

@goformit100 u should take a sleep

Answer 23

Post the Question in the correct Section. Sir Please Close the Question Here.....

Answer 24

What would Saxon do here? why did you tag her?????

Answer 25

yes i posted it in chemistry section but no one was there to solve my query @goformit100

Answer 26

WWSD

What Would Saxon Do

Answer 27

@Johnbc hlp doing me the question

Answer 28

But You are breaking the Code of Conduct of the Site. We May Report you For Not Understanding the importance of posting question in the correct Section.

Answer 29

@kanwal32 Sir Please Close the Question.

Answer 30

i will do sfter getting the solution

Answer 31

Saying that Dk = 4 and half of that is the diameter\[\frac{ 4 \pi (\frac{ 1 }{2 })^2 }{ 3 } = \frac{ 4(\frac{ 4 }{ 3 } \pi (1k/2)^2) }{ n^2 }\]

Answer 32

yes

Answer 33

You have 2 variables and 1 equation

Answer 34

cancelling 4/3pi on both the sides

Answer 35

yes @Johnbc

Answer 36

We can try it that way so if we leave all variables and cancel we have:\[r_i^2= \frac{ 4r_f^2 }{ n_2 }\]

Answer 37

its r^3

Answer 38

i think @Johnbc

Answer 39

right r^3 but you still have 2 variables because Dk = P2

Answer 40

So you need to solve for k

Answer 41

yes

Answer 42

\[1k= 4\]\[k = 4\]

Answer 43

yeah

Answer 44

radius after is half of dk so it would be\[r =\frac{ 4d }{ 2 } = 2d\]

Answer 45

so you will now have:\[(\frac{ 1 }{ 2 })^3=\frac{ 4(2d)^2 }{ n_2 }\]...

Answer 46

I guess using Dk= P2 we can solve for d at 4 atm
D(2) = 4 or D = 2

Answer 47

A balloon containing 1 mole air at 1 atm initiallyis filled further with air till pressure increases to 4 atm. The initial diameter of the ballon is 1m and the pressure at each stage is proportion to diameter of the balloon. How many moles of air are needed to change the pressure to 4atm

Let the initial pressure be \(\LARGE P_i\) and final one be \(\LARGE P_f\).
Initial Diameter and radius = \(\LARGE D_i\) and \(\LARGE D_f\) respectively.
Question says D is directly proportional to P
Now if prssure becomes 4 times the normal one then Diameter MUST also become 4 times the normal one.
As we now \[\Large V= \frac{4}{3} \pi r^3\]
d->4d
r->8r
As nothing has been specified I assume that the temperautre is constant so we can use Charle's law
\[\Large \frac{P_1 V_1}{n_1} = \frac{P_2 V_2}{n_2}\]
we need to solve for \(\LARGE n_2\) and we know rest of the stuff.
Can you do it now?

Answer 48

gottcha

Answer 49

but the answer is wrong

Answer 50

What is the answer?