what is the sum of the geometric series 15 E x=0 2(1/2)^x........... this is summation notation here..!!
@ganeshie8
@jim_thompson5910
@Luigi0210
@mathstudent55 ............sum help would be great....
well find the first few terms x = 0 2 x = 1 1 x = 2 1/2 x = 3 1/4 so the 1st term is 2, the common ratio is r = 1/2 and the number of terms is n = 16 since you are going from 0 to 15 so use the formula \[S_{n} = \frac{a(1 - r^n)}{(1 - r)}\] hope it helps
right^
@campbell_st ........thanks a TON.......... just had some doubts.....
k thx.... appreciate it
\[\Huge \sum_{0}^{15} \frac{2}{2^x}= 2+ 1 + \frac{1}{2} + \frac{1}{4}....\] 3+ (sum of a GP)
\[\Huge S_n = \frac{a(1- r^n)}{1-r}\] where a is your first term and r the common difference
should be 4 right...?
\[\LARGE 3+\frac{\frac{1}{2} ( 1- \frac{1}{2^{14}})}{\frac{1}{2}}\] this should be your answer I guess
yup... it;s 4......... thanks a lot @DLS
yeah one..because \[\LARGE \frac{1}{2^{14}} ->0\] since its a very large quantity :)
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