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Solve for z 6=1/6z+8
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\[6 = \frac{ 1 }{ 6 }z + 8\] ?
Yea
well. we can say: \[6 - 8 = \frac{ 1 }{ 6 } z + 8 - 8\]
like: a = a so a - 8 = a -8 9 = 9 --> 9 - 8 = 9 - 8 >> 1 = 1
ok?
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Wait i dont get it i dont think thats correct.
@iGreen
well, please give me an example that its not CORRECT!
\(6 = \dfrac{ 1 }{ 6 }z + 8\) \(-\dfrac{ 1 }{ 6 }z = 8 - 6\) \(-\dfrac{ 1 }{ 6 }z = 2\) \(z = \dfrac{1}{3}\)
Sorry that's -1/3
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Yea you were incorrect. Can you see what the question was @PFEH.1999?? Thanks @iGreen
Well @PFEH.1999 was right here: \(6 - 8 = \dfrac{ 1 }{ 6 } z + 8 - 8\) Which will give us: \(-2 = \dfrac{ 1 }{ 6 } z\) Multiply: \(z = -\dfrac{1}{3}\)
these questions can be solved by different ways :)
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