The area of a rectangle is 48 square feet. The length is two feet longer than the width. What is the width of the rectangle?
What are the factors of 48
none were given
You should know the factors of 48
1,2,3,4,6,8,12,16,24,48
Well, my way is a little weird but here's how I'd solve it: Set up an algebraic equation: We know that area=width*length We also know that the area is 48, and that the length is 2 feet longer than the width. So we now have: 48 =N*(N+2) Because the one side is 2 feet longer than the other, and we don't know the length of either. 48=N^2 +2N N=6. So the width is 6, and the length is 8 (6+2)
thank you
I can see what army was trying to show you. You could see that 6 and 8 were both factors of 48, and that 8 was 2 bigger than 6, so your length was 8 and your width was 6. There explanation was a little better. :)
Thanks fort he pat on the back
Join our real-time social learning platform and learn together with your friends!