Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°.
I ended with r=3(sqroot2) I'm not sure how to progress since the answer choices are
(3 square root of 2, 315°), (-3 square root of 2, 135°) (3 square root of 2, 225°), (-3 square root of 2, 45°) (3 square root of 2, 45°), (-3 square root of 2, 225°) (3 square root of 2, 135°), (-3 square root of 2, 315°)
Im stuck idk how to apply the degrees
refreshing right now...BRB
okay
I am getting one of them to be\[(3\sqrt{2},-\frac{ \pi }{ 4 })\]and I think the other would be\[(-3\sqrt{2},-\frac{ \pi }{ 4 })\]That is the best i can do with trying to remember the conversion, ok?
or maybe it is\[(3\sqrt{2},-\frac{ \pi }{ 4) } \]or\[(3\sqrt{2},-45)\]I think these are the correct answers, to tell you the truth. One is in radians and the other degrees.
*\[(3\sqrt{2},-\frac{ \pi }{ 4 })\]
pi over 4 is also 45 degrees.
Those are the two ways to write (3,-3) in polar form.
The angle must be between 0 and 360 according to the qyestion
The other representation is \[ \left (-3 \sqrt{2},\frac{3 \pi }{4}\right) \]
The answer is \[ \left (3 \sqrt{2},\frac{7 \pi }{4}\right)\\ and \\ \left(-3 \sqrt{2},\frac{3 \pi }{4}\right) \]
@IMStuck @eliassaab Thank you. My internet got cut off
NP
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