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Mathematics 16 Online
OpenStudy (anonymous):

medal and follow promise

OpenStudy (anonymous):

Based on the histogram, how many students were included in the survey? What percentage of the students surveyed babysat for at most eleven hours last weekend? Show your work.

OpenStudy (anonymous):

OpenStudy (anonymous):

@minoz @AngelWilliams16 @Hipsterlife1 @xiphoidx @undeadknight26

OpenStudy (anonymous):

for no of students add all hrs no of students i.e., 5 for (0-3),10 for (4-7)..=5+10+25+40

OpenStudy (anonymous):

atmost means not more than so count all the students who sit max 11 hrs=i.e., count for (0-3)+(4-7)+(8-11)

OpenStudy (anonymous):

it would be?

OpenStudy (kirbykirby):

Since there are 5+10+25+40 = 80 students in total, and the number working at most 11 hours is: 5 + 10 + 25 = 40, then the percentage of students working at most 11 hours is: \[ \frac{40}{80}=0.5=50\%\]

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