Question

The vertex form of the equation of a parabola is y = 5(x - 3)2 ­- 6. What is the standard form of the equation?

pic - http://i.imgur.com/ekbjOQH.png

Answer 1

Okay so here;s the steps! \[5(x-3)^{^{2}} -6\]
the you get
5(x-3)(x-3)-6
then you get
\[5(x ^{2} -3x-3x+9)\]
then multiply 5
\[(5x ^{2} -30x +45) -6\]
the last step is 45-6 is 39 so your answer will be...
\[5x ^{^{2}} -30x +39\]

Answer 2

:)

Answer 3

@linda3 thank you! ;)

Answer 4

your most very welcome!

Answer 5

another approach
vertex (h, k)
h = -b/2 a and k =- a(-b/2 a)^2 + c
a = 5
3 = -b/2*5 so b =-30

(-b/2a)^2 =(-30/10)^2 = 9
-6 = -5(9)+ c so c = 45 - 6 = 39

5 x^2 -30 x + 39

Answer 6

@triciaal thank you!! ;)