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Mathematics 15 Online
OpenStudy (anonymous):

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 37ft/s. The balls height h (in feet) after t seconds is given by the following. H=2+37t-16t^2 Find all values of t for which the balls height is 22 feet. Round your answer to the nearest hundredth

OpenStudy (anonymous):

Make h=22 then solve for t

OpenStudy (anonymous):

So I would do 22=2+37t-16t^2. Then subtract 2 from both sides?

OpenStudy (anonymous):

I don't understand because I'll still have a t and a t^2 value

OpenStudy (anonymous):

Subtract 22 from both sides what do you have?

OpenStudy (anonymous):

0=-20+37t-16t^2?

OpenStudy (anonymous):

Now solve for t using the quadratic formula?

OpenStudy (anonymous):

So solve -16t^2+37t+29 in quadratic formula

OpenStudy (anonymous):

Yes and that should be +20 not +29

OpenStudy (anonymous):

For every value where t is positive will be your answers.

OpenStudy (anonymous):

So I got -37+or- square root of 2649/-64...I don't understand where t is positive. I'm so sorry I'm so confused

OpenStudy (anonymous):

I got 2 neg values...should I get that?

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