A ball is thrown from an initial height of 2 feet with an initial upward velocity of 37ft/s. The balls height h (in feet) after t seconds is given by the following.
H=2+37t-16t^2
Find all values of t for which the balls height is 22 feet.
Round your answer to the nearest hundredth
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OpenStudy (anonymous):
Make h=22 then solve for t
OpenStudy (anonymous):
So I would do 22=2+37t-16t^2. Then subtract 2 from both sides?
OpenStudy (anonymous):
I don't understand because I'll still have a t and a t^2 value
OpenStudy (anonymous):
Subtract 22 from both sides what do you have?
OpenStudy (anonymous):
0=-20+37t-16t^2?
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OpenStudy (anonymous):
Now solve for t using the quadratic formula?
OpenStudy (anonymous):
So solve -16t^2+37t+29 in quadratic formula
OpenStudy (anonymous):
Yes and that should be +20 not +29
OpenStudy (anonymous):
For every value where t is positive will be your answers.
OpenStudy (anonymous):
So I got -37+or- square root of 2649/-64...I don't understand where t is positive. I'm so sorry I'm so confused
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