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Mathematics 13 Online
OpenStudy (anonymous):

You roll two dice. Define the events A and B as: Event A = At least one die shows a 4 Event B = The sum of the dice is greater than 5

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

All of question is in attachment

OpenStudy (kirbykirby):

OpenStudy (kirbykirby):

A. The probability where one die is at least one die shows a 4: Count the number of circled events and divide by the total # of squares (the total number of outcomes). B. The probability that the sum of the dice is greater than 5: Count the number of squares with a line through them, and divide by the total number of outcomes. C. P(one die at least 4 AND sum is greater than 5) is going to the intersection of both of those events (i.e. the squares that are BOTH red circles and have a blue line). D. P(one die at least 4 OR sum is greater than 5) is going to be the union of both of those events (i.e. all the squares that have a red circle, and those with a blue line... count all of those (the squares that are both blue and red must be counted as well, but don't count them twice))

OpenStudy (anonymous):

is the first one then 11/36?

OpenStudy (kirbykirby):

yup!

OpenStudy (anonymous):

2nd 27/36?

OpenStudy (anonymous):

i dont undertand c or d

OpenStudy (kirbykirby):

Hm I counted 26/36

OpenStudy (anonymous):

i probably just counted wrong happens all the time haha

OpenStudy (kirbykirby):

hehe

OpenStudy (kirbykirby):

So P(A "AND" B) .. with "AND" it means that you are looking for the squares that satisfy both A and B (i.e. the squares that are circled in red and lined in blue at the same time) And P(A "OR" B)... with "OR" it means that you are looking for the squares that satisfy A, or B, or both (i.e. the squares that are circled in red, or lined in blue, or both)

OpenStudy (anonymous):

is c 9/36? and d 28/36

OpenStudy (kirbykirby):

yes and yes :)

OpenStudy (anonymous):

thank you!!!! :)

OpenStudy (kirbykirby):

your welcome!

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