Simple Equation Involving x and y : \[\frac{y-1}{ x+3 } =-\frac{ 3 }{ 4 }\]
@wolf1728
someone please explain step by step
well now.. solve them independently
what is y - 1 = 3
and what is x+1 = 4
I mean, can i just do the cross muliplying ?
why would you cross multiply? you're not doing a proportion you're solving for possible values of x and y
\[(y-1)*4=-3*(x+3)\]
go ahead
:/ mmm so...
that should give you a distributive property on the left and on the right side of the equation try solving it with your method
i guess is wrong already, what do i have to do, please i can't fail on this one
do you have ten fingers?
ahh ? i guess is a JK thing of yours
I want to know if you have ten fingers, because I don't want to assume that you do
hey dude, i doin on't have a lot of time like you think so, so I'm going to solve in the way i told you
okay then do it your way I was going to show you a trick that you can base your future algebra problems with
if you don't have ten fingers just tell me, I won't judge you
\[4y-4 = -3x-9\]
did it help you solve for x and y?
you're doing an equation, where is that solution going to lead you?
to nowhere
exactly
we're going to try to solve for y put three fingers up
maybe a function thing..
just put three fingers up
lol go ahead
okay it says y - 1 = 3 with your three fingers up, that is your right hand side of the equation now on the left hand side it says y - 1 how about you add 1 to find out how many you had before one was deducted
done?
now you know how the mechanism is done, let me lay it out for you y - 1 = 3 //add 1 to both sides of the equation y -1 + 1 = 3 + 1 //the left hand side becomes y because -1 + 1 becomes zero y + 0 = 4 // finalize y = 4 do the same thing with the x in the denominator and tell me what you got
i have to describe every step
what kind of property is that ?
i need t
to inform! please come back dude. please help me out
http://coolmath.com/prealgebra/06-properties/07-properties-additive-inverse-01.htm
it applies to variables too
I know that ! what i was saying is related with the whole approach in the equation
it has no specific name like cross multiplication
I'm going to trust in you,but if i fail, iLL be screwed..
you won't how about you tell me what you got for x?
because we are not done yet
x=1
okay plug those into the original equation but you will notice that the right hand side is a negative
yes...
the rule is that for a fraction to be negative, either the numerator or denominator has to be negative
so let us tweak either the numerator or denominator. you pick which would you like to be the negative on the right hand side
I didn't know that i can solve the equation in this way, hope is right
y/x = -4 ?
doesn't make sense for me
\[\frac{y-1}{ x+3 } =-\frac{ 3 }{ 4 }\]
4y=−3x−5, \[y =-\frac{ 3x }{ 4 }-\frac{ 5 }{ 4 }\]
no
just pick if you want the numerator or the denominator on the right side to be negative
dude thanks anyway...
okay
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