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Geometry 19 Online
OpenStudy (anonymous):

I do not grasp the concept of finding the measurements of arcs. Please help *pics added in comments

OpenStudy (anonymous):

OpenStudy (anonymous):

I have to find arc KIM..and I got 235

OpenStudy (anonymous):

I also do not know how to find the measurement of minor arc GH in problem #2.

OpenStudy (anonymous):

My instructor keeps having me redo these problems, but is not telling me what I did wrong after repeatedly asking :/

OpenStudy (nikato):

i dont think KIM is 235

OpenStudy (anonymous):

How do I find KIM

OpenStudy (nikato):

|dw:1405402817106:dw|

OpenStudy (nikato):

you should know arcMN is 80 because its the same measure as the central angle

OpenStudy (nikato):

do you know the measure of arcJK

OpenStudy (anonymous):

would that be 80 too?

OpenStudy (nikato):

correct

OpenStudy (nikato):

|dw:1405403441437:dw|

OpenStudy (nikato):

and we know arcJKM=180

OpenStudy (anonymous):

correct because it is half of the circle

OpenStudy (nikato):

and lets call arcKM x so 80+x=180 so whats x?

OpenStudy (anonymous):

100

OpenStudy (nikato):

correct. so whats <KIM?

OpenStudy (anonymous):

or 100

OpenStudy (nikato):

no. 100 remember the central angle is the same measure as its intercepted arc since we found that its intercepted arc, KM=100, then <KIM also =100

OpenStudy (anonymous):

ok, I get it now. Thanks a bunch nikato

OpenStudy (nikato):

no problem. and do you need help on the second one then?

OpenStudy (anonymous):

Is there another method that I would have to use for the second problem since it is a minor arc

OpenStudy (nikato):

no. this would be the simplest method. and there would just be one less step for this second problem

OpenStudy (nikato):

becuz everything you need is already given to you

OpenStudy (anonymous):

I think I can solve it now

OpenStudy (nikato):

ok

OpenStudy (anonymous):

would this be the correct equation 70+x=180

OpenStudy (nikato):

no. should be 120+x=180

OpenStudy (anonymous):

Or do I need to incorporate the 120 somewhere

OpenStudy (nikato):

we know arcGHD=180] and arcHD=120 and lets call GH x

OpenStudy (anonymous):

ok

OpenStudy (nikato):

because arcHD + arcGH = arcGHD

OpenStudy (nikato):

its kinda like substitution once you find the equation

OpenStudy (anonymous):

So x=60

OpenStudy (nikato):

Correct

OpenStudy (anonymous):

Wow thanks. So the 70 degrees in the problem was sort of irrelevant?

OpenStudy (nikato):

Yea. It wasn't sort of irrelevant. It WAS irrelevant. Maybe there to throw you off

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