Geometry
19 Online
OpenStudy (anonymous):
I do not grasp the concept of finding the measurements of arcs. Please help
*pics added in comments
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OpenStudy (anonymous):
OpenStudy (anonymous):
I have to find arc KIM..and I got 235
OpenStudy (anonymous):
I also do not know how to find the measurement of minor arc GH in problem #2.
OpenStudy (anonymous):
My instructor keeps having me redo these problems, but is not telling me what I did wrong after repeatedly asking :/
OpenStudy (nikato):
i dont think KIM is 235
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OpenStudy (anonymous):
How do I find KIM
OpenStudy (nikato):
|dw:1405402817106:dw|
OpenStudy (nikato):
you should know arcMN is 80 because its the same measure as the central angle
OpenStudy (nikato):
do you know the measure of arcJK
OpenStudy (anonymous):
would that be 80 too?
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OpenStudy (nikato):
correct
OpenStudy (nikato):
|dw:1405403441437:dw|
OpenStudy (nikato):
and we know arcJKM=180
OpenStudy (anonymous):
correct because it is half of the circle
OpenStudy (nikato):
and lets call arcKM x
so
80+x=180
so whats x?
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OpenStudy (anonymous):
100
OpenStudy (nikato):
correct.
so whats <KIM?
OpenStudy (anonymous):
or 100
OpenStudy (nikato):
no.
100
remember the central angle is the same measure as its intercepted arc
since we found that its intercepted arc, KM=100,
then <KIM also =100
OpenStudy (anonymous):
ok, I get it now. Thanks a bunch nikato
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OpenStudy (nikato):
no problem.
and do you need help on the second one then?
OpenStudy (anonymous):
Is there another method that I would have to use for the second problem since it is a minor arc
OpenStudy (nikato):
no. this would be the simplest method. and there would just be one less step for this second problem
OpenStudy (nikato):
becuz everything you need is already given to you
OpenStudy (anonymous):
I think I can solve it now
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OpenStudy (nikato):
ok
OpenStudy (anonymous):
would this be the correct equation 70+x=180
OpenStudy (nikato):
no. should be
120+x=180
OpenStudy (anonymous):
Or do I need to incorporate the 120 somewhere
OpenStudy (nikato):
we know arcGHD=180]
and arcHD=120
and lets call GH x
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OpenStudy (anonymous):
ok
OpenStudy (nikato):
because
arcHD + arcGH = arcGHD
OpenStudy (nikato):
its kinda like substitution once you find the equation
OpenStudy (anonymous):
So x=60
OpenStudy (nikato):
Correct
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OpenStudy (anonymous):
Wow thanks. So the 70 degrees in the problem was sort of irrelevant?
OpenStudy (nikato):
Yea. It wasn't sort of irrelevant. It WAS irrelevant. Maybe there to throw you off