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Solve following equation for............., in terms of pi
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|dw:1405409291771:dw|
4sinx - 7= 2cosecx
I recommend multiplying both sides by sin(x) to start off
tell me what you get
well cosec= 1/sin so multiply every term by sin(x) and you get \[4\sin^2(x) - 7\sin(x) = 2\] so now you are solving a quadratic
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4sin^2x-7sinx-2=0 @campbell_st
let z = sin(x) we have 4z^2 - 7z - 2 = 0 solve for z
|dw:1405409830784:dw|
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