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Mathematics 13 Online
OpenStudy (eric_d):

Solve following equation for............., in terms of pi

OpenStudy (eric_d):

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OpenStudy (eric_d):

4sinx - 7= 2cosecx

jimthompson5910 (jim_thompson5910):

I recommend multiplying both sides by sin(x) to start off

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (campbell_st):

well cosec= 1/sin so multiply every term by sin(x) and you get \[4\sin^2(x) - 7\sin(x) = 2\] so now you are solving a quadratic

OpenStudy (eric_d):

4sin^2x-7sinx-2=0 @campbell_st

jimthompson5910 (jim_thompson5910):

let z = sin(x) we have 4z^2 - 7z - 2 = 0 solve for z

OpenStudy (eric_d):

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