Help please If f(x) = 8 – 3|x + 2|, find f(–6) A. 4 B. 20 C. –16 D. –4
Identify the graph of f(x) = 2|x + 3|. A. http://static.k12.com/calms_media/media/330000_330500/330020/1/374a4c4ca0cc3829ab7548e16e47da2adc2c39af/MS_ALG_S2_01_08_quiz_Q4b_question.gif B. http://static.k12.com/calms_media/media/330000_330500/330022/1/94c59fa370d9a0b4d11ac6a9c17b99b5a370831f/MS_ALG_S2_01_08_quiz_Q4d_question.gif C. http://static.k12.com/calms_media/media/330000_330500/330021/1/2acd7269b43f99912cbf0199a44f1b1cef85b5fd/MS_ALG_S2_01_08_quiz_Q4c_question.gif D. http://static.k12.com/calms_media/media/330000_330500/330019/1/180a3841bdca9324e56b3bc1b4561a5631c190bb/MS_ALG_S2_01_08_quiz_Q4a_question.gif
@dan815 @goformit100 @phi @campbell_st @agent0smith
you need the answer ?
One question at a time. If f(x) = 8 – 3|x + 2|, find f(–6) All you have to do is plug -6 into the equation.
sorry I was afk but the first question would be... A?
no it would be D
that was my second guess, I always get mixed up with the negatice and positive number's when using "|" XD thank you
yw
can you help with me the second one?
what would the graph look like when its absolute?
A and C?
Im going with C
or thats what I think it is
no
ok um.. what would x be?
any thing actually
its an absolute
oh ok so any positive number that matches the graph?
yes
k :) um... were looking for a graph this is absolute right?
yes
the best graph that i see that fits all my numbers A
can you help me with one more?
sure
thanks =D
Write the equation for the graphed func http://static.k12.com/calms_media/media/330000_330500/330023/1/5dfe814f1ae1e7ca480a0700d7f49a381f8fa057/MS_ALG_S2_01_08_quiz_Q5_question.gif A. f(x) = |x| + 2 B. f(x) = |x| – 2 C. f(x) = |x – 2| D. f(x) = |x + 2|tion.
Im thinking B but I could be wrong, ( I'm bad at using graphs)
hmm
wait I don't think that there should be a "tion" on answer D.
let me check
oops sorry :( dont know were that came from...
lol ok so did you try putting random numbers from the graph into the equations?
yes and no, I did but im confused
wait one thing that you should know. if you have a equation like that f(x) = |x| + 2 your graph would look like|dw:1405413449386:dw|
so A is out?
but if you have these kind of equations f(x) = |x – 2| your graph would look like this |dw:1405413516425:dw|
yes A is out
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