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Mathematics 22 Online
OpenStudy (anonymous):

Help please If f(x) = 8 – 3|x + 2|, find f(–6) A. 4 B. 20 C. –16 D. –4

OpenStudy (anonymous):

@dan815 @goformit100 @phi @campbell_st @agent0smith

OpenStudy (anonymous):

you need the answer ?

OpenStudy (agent0smith):

One question at a time. If f(x) = 8 – 3|x + 2|, find f(–6) All you have to do is plug -6 into the equation.

OpenStudy (anonymous):

sorry I was afk but the first question would be... A?

OpenStudy (anonymous):

no it would be D

OpenStudy (anonymous):

that was my second guess, I always get mixed up with the negatice and positive number's when using "|" XD thank you

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

can you help with me the second one?

OpenStudy (anonymous):

what would the graph look like when its absolute?

OpenStudy (anonymous):

A and C?

OpenStudy (anonymous):

Im going with C

OpenStudy (anonymous):

or thats what I think it is

OpenStudy (anonymous):

no

OpenStudy (anonymous):

ok um.. what would x be?

OpenStudy (anonymous):

any thing actually

OpenStudy (anonymous):

its an absolute

OpenStudy (anonymous):

oh ok so any positive number that matches the graph?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

k :) um... were looking for a graph this is absolute right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the best graph that i see that fits all my numbers A

OpenStudy (anonymous):

can you help me with one more?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

thanks =D

OpenStudy (anonymous):

Write the equation for the graphed func http://static.k12.com/calms_media/media/330000_330500/330023/1/5dfe814f1ae1e7ca480a0700d7f49a381f8fa057/MS_ALG_S2_01_08_quiz_Q5_question.gif A. f(x) = |x| + 2 B. f(x) = |x| – 2 C. f(x) = |x – 2| D. f(x) = |x + 2|tion.

OpenStudy (anonymous):

Im thinking B but I could be wrong, ( I'm bad at using graphs)

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

wait I don't think that there should be a "tion" on answer D.

OpenStudy (anonymous):

let me check

OpenStudy (anonymous):

oops sorry :( dont know were that came from...

OpenStudy (anonymous):

lol ok so did you try putting random numbers from the graph into the equations?

OpenStudy (anonymous):

yes and no, I did but im confused

OpenStudy (anonymous):

wait one thing that you should know. if you have a equation like that f(x) = |x| + 2 your graph would look like|dw:1405413449386:dw|

OpenStudy (anonymous):

so A is out?

OpenStudy (anonymous):

but if you have these kind of equations f(x) = |x – 2| your graph would look like this |dw:1405413516425:dw|

OpenStudy (anonymous):

yes A is out

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