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OpenStudy (anonymous):
What's the question
OpenStudy (anonymous):
What is the y-intercept of the line represented by the equation below?
y = –2x – 1
OpenStudy (anonymous):
it is -1
OpenStudy (anonymous):
thankssss
OpenStudy (anonymous):
The last number in the slope-intercept form of y=mx+b is always the y-intercept.
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OpenStudy (anonymous):
What is the equation of the line that passes through the points (2, –1) and (6, 1)?
OpenStudy (anonymous):
First find the slope with the equation y2-y1/x2-x1=1-(-1)/6-2=2/4=1/2 is the slope.
now put the slope and the x and y intercept into the point-slope formula like this:
\[y-y _{1}=m(x-x _{1})\]
\[y-2=1/2(x-(-1))\] The minus negative 1 becomes +1
\[y-2=1/2(x+1)\] Distribute the 1/2 to x+1
\[y-2=1/2x+1/2\] now add 2 to both sides
\[y=1/2x+2\frac{ 1 }{ 2 }\] is the slope-intercept form
OpenStudy (anonymous):
Does this help @Dequavia123
OpenStudy (anonymous):
is 1/2x-2
OpenStudy (anonymous):
What?
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OpenStudy (anonymous):
the answer is 1/2x-2?
OpenStudy (anonymous):
no for slope-intercept form it is
\[y=1/2x+2\frac{ 1 }{ 2 }\]