some one plzz help
Solve the system of equations.

x + 3y = -1
2x + 2y = 6

(-4, 1)

(2, -1)

(4, -1)

(5, -2)

Question

some one plzz help
Solve the system of equations.

x + 3y = -1
2x + 2y = 6

 (-4, 1)

 (2, -1)

 (4, -1)

 (5, -2)

anonymous · Answer

multiply the first equation by 2, then subtract the second equation from it.

igreen · Answer

Solve for $x$ in the first equation:

$x + 3y = -1$
$x = -3y - 1$

anonymous · Answer

ok so  the second equation would becom 2(-3y-1) + 2y=6

igreen · Answer

Now we can plug in $-3y-1$ for $x$ in the second equation:

$2(-3y-1) + 2y = 6$

Solve for $y$:

$-6y - 2 + 2y = 6$
$-6y + 2y = 8$
$-4y = 8$
$y = -2$

igreen · Answer

Yes, that's right. @elketen

anonymous · Answer

thanks a lot

igreen · Answer

Now we have our y-value, -2. Then we can plug it into any of the equations:

$x + 3y = -1$
$x + 3(-2) = -1$
$x - 6 = -1$
$x = 5$

igreen · Answer

So the solution is $(5,-2)$.

anonymous · Answer

ok i get it  thanks i was confuse

igreen · Answer

No problem :)

anonymous · Answer

can you help me with another one

anonymous · Answer

@iGreen

igreen · Answer

No problem. Just close this and open another one.