How do I solve for x

log3x + log34 = 2

Question

How do I solve for x 

log3x + log34 = 2

anonymous · Answer

@aum this is the equation, I have no clue how to do this

anonymous · Answer

Hint: log39=2

anonymous · Answer

how'd you get that @Saeeddiscover

anonymous · Answer

logab=c  --> b=a^c

aum · Answer

$ \Large
\log_3x + \log_34 = 2 \ \Large
\log_3(4*x) = 2 \ \Large
4x = 3^2 = 9 \ \Large
x = 9/4 = 2\frac 14
$

aum · Answer

$\Large \log(AB) = \log(A) + \log(B) $

$\Large \log_bA = C ~~\text{ implies }~~A = b^C$

anonymous · Answer

is that complete ?
like step by step

anonymous · Answer

I'm confused @ aum

anonymous · Answer

@aum im confused

jdoe0001 · Answer

phi · Answer

phi · Answer