Solve for x: 3x to the second power+ 7x=2
\(\sf 3x \color{red}{^2}+7x=2 \Rightarrow 3x^2+7x-2=0\)
dont know where to go from there
You need to use this thing called discriminant and equation it is used in http://en.wikipedia.org/wiki/Discriminant
for discriminant in school we used letter d, so i will use it there also you have this equation 3x^2 +7x - 2 = 0 , but to determine letters in later used formulass you must first know this example: ax^2 +bx +c = 0 , from wich you get that your's a is equal 3, b is equal 7 and c is equal -2, now determinant d = b^2 -4ac there is also a quick way to tell how many variants of x you will have y finding value of determinant d >0 means you have 2 variants d = 0 means you have one d< 0 means equation can not be solved or is somewhat wicked
as for when you have found value of determinant (given your discriminant value is more then zero), you now can use these formulas: x1 = (-b + squareroot(d) )/2a and x2 = (-b - squareroot(d) )/2a second case - so, if discriminant is value 0, then you square root zero, meaning x1=x2 last case - since you can't "pull" square root from negative number, then x cannot be found
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