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Geometry 6 Online
OpenStudy (anonymous):

How do I solve for x? (2 questions) *Pics in comments

OpenStudy (anonymous):

OpenStudy (anonymous):

#2 Solve for x

OpenStudy (jdoe0001):

?

OpenStudy (anonymous):

That's the only information the assignment gave me. Just to solve for the value of "x"

OpenStudy (jdoe0001):

http://www.mathopenref.com/thalestheorem.html <--- notice the triangle from a subtended diameter

OpenStudy (jdoe0001):

thus is always 90 degrees on the circumferencial angle... thus , is always a right triangle

OpenStudy (anonymous):

I am following

OpenStudy (jdoe0001):

so that means that |dw:1405469145768:dw| thus \(\bf \cfrac{1}{2}x+\cfrac{1}{3}x+5=90\) and then you can just solve for "x"

OpenStudy (jdoe0001):

as far as the 2nd one -> http://www.geom.uiuc.edu/~dwiggins/conj47.html <--- notice also, opposite sides are "supplementary angles" thus |dw:1405469513461:dw|

OpenStudy (anonymous):

So I set them equal to 180?

OpenStudy (jdoe0001):

yeap

OpenStudy (jdoe0001):

(3x-8) + (5x+2) = 180

OpenStudy (anonymous):

x=93/4

OpenStudy (anonymous):

for the #2?

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

thanks

OpenStudy (jdoe0001):

yw

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