How do I solve for x? (2 questions) *Pics in comments
#2 Solve for x
?
That's the only information the assignment gave me. Just to solve for the value of "x"
http://www.mathopenref.com/thalestheorem.html <--- notice the triangle from a subtended diameter
thus is always 90 degrees on the circumferencial angle... thus , is always a right triangle
I am following
so that means that |dw:1405469145768:dw| thus \(\bf \cfrac{1}{2}x+\cfrac{1}{3}x+5=90\) and then you can just solve for "x"
as far as the 2nd one -> http://www.geom.uiuc.edu/~dwiggins/conj47.html <--- notice also, opposite sides are "supplementary angles" thus |dw:1405469513461:dw|
So I set them equal to 180?
yeap
(3x-8) + (5x+2) = 180
x=93/4
for the #2?
yeap
thanks
yw
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