Question

plzzzzz help

Answer 1

Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.



38 and 40

40 and 42

42 and 44

Answer 2

40 and 42

Answer 3

Here is why

Answer 4

let the smaller number by 2x and the larger 2x + 2 (since even and consecutive)
half of the larger is x + 1
two fifths of the smaller gives four fifths x
so \[x + 1-\frac{ 4 }{ 5 }x=5\]

Answer 5

mk

Answer 6

so one fifth x = 4
hence x = 20 so the smaller number is 2x = 40 and the larger is 2x + 2 = 42

Answer 7

your smater than me