Question

write an equation of the line containing the specified point and perpendicular to the indicated line. (3, 1), 2x-3y=4

Answer 1

1st find the slope of indicated line i.e

3y=2x-4
=>y=2/3x-4/3

here slope=2/3
but if the required line is perpndicular to indicate then ultiply slope by -1 i.e slope=m=-2/3
so
now point slope form is

(y-y1)=m(x-x1)

(y-1)=-2/3(x-3)
=>3(y-1)=-2(x-3)
=?3y-3=-2x+6
=>3y+2x=9
answer

Answer 2

get it..???

Answer 3

Yes, thank you so much :)

Answer 4

you welcome...

Answer 5

You need to take the opposite reciprocal to get a perpendicular line, and not just the opposite @zaibali.qasmi?

Answer 6

So m = -3/2 not -2/3