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what is the y coordinate of the vertex of the parabola that is givenby the equation bellow: x = -2.5(x-3)^2 + 5
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The general equation in vertex form is given by: \((y-k)=a(x-h)^2\) for a parabola with vertical axis or \((x-h)=a(y-k)^2\) for a parabola with horizontal axis. where (h,k) represents the vertex. I suspect there is a typo in the question where the equation should read: \(y=-2.5(x-3)^2+5\) which is a parabola with vertical axis
sorry I typed it wrong, its \[x = -2.5(y-3)^2 + 5\]
In that case, it is a parabola with a horizontal axis. But the coordinates (h,k) still apply. It looks approximately like this. |dw:1405527373059:dw|
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