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Exponents
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\[\Huge 2^{2014}-2^{2013}\]
hint : 2014 = 2013 + 1
\[\large 2^{2013 + 1}-2^{2013}\]
2^2013 * 2^1 - 2^2013
yes pull out the common factor 2^2013
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2^2013(2-1)
2^2013(1)
@ganeshie8
looks good :) so you found this nice pattern for powers of 2, nice :)
no , they want a perfect answer
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\[\huge 2^{n+1}-2^n = 2^n\]
whats a perfect answer ?
i mean number , not in exponents like 4,5,6,7,7,7
nonsense question this is , but i asked because i was confused
maybe give them the wolfram link http://www.wolframalpha.com/input/?i=2%5E2014+-+2%5E2013
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It is accepting the answer lol
good :)
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