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Mathematics 8 Online
OpenStudy (anonymous):

Exponents

OpenStudy (anonymous):

\[\Huge 2^{2014}-2^{2013}\]

ganeshie8 (ganeshie8):

hint : 2014 = 2013 + 1

ganeshie8 (ganeshie8):

\[\large 2^{2013 + 1}-2^{2013}\]

OpenStudy (anonymous):

2^2013 * 2^1 - 2^2013

ganeshie8 (ganeshie8):

yes pull out the common factor 2^2013

OpenStudy (anonymous):

2^2013(2-1)

OpenStudy (anonymous):

2^2013(1)

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

looks good :) so you found this nice pattern for powers of 2, nice :)

OpenStudy (anonymous):

no , they want a perfect answer

ganeshie8 (ganeshie8):

\[\huge 2^{n+1}-2^n = 2^n\]

ganeshie8 (ganeshie8):

whats a perfect answer ?

OpenStudy (anonymous):

i mean number , not in exponents like 4,5,6,7,7,7

OpenStudy (anonymous):

nonsense question this is , but i asked because i was confused

ganeshie8 (ganeshie8):

maybe give them the wolfram link http://www.wolframalpha.com/input/?i=2%5E2014+-+2%5E2013

OpenStudy (anonymous):

It is accepting the answer lol

ganeshie8 (ganeshie8):

good :)

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