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Mathematics 20 Online
OpenStudy (anonymous):

given the function: f(x)=-2x^2-3x+6 Find: f(4)-f(-5)

OpenStudy (anonymous):

well,first find f(4) you can substitute 4 instead of x

OpenStudy (anonymous):

but what about the -5?

OpenStudy (anonymous):

ok we'll solve it little by little ;) first find f(4) then i'll tell u what do do ;)

OpenStudy (anonymous):

26

OpenStudy (anonymous):

oh ok then i find f(5) and subtract right?

OpenStudy (anonymous):

i think you've made a mistake ... try it again.

OpenStudy (anonymous):

hm

OpenStudy (anonymous):

YES! you're very fast to learn :) then we should subtract them...

OpenStudy (anonymous):

-38 forgot the negative

OpenStudy (anonymous):

yes,correct and then find f(-5) and then subtract them and give me the final answer :)

OpenStudy (anonymous):

-97?

OpenStudy (anonymous):

no...try it again what is f(-5) ?

OpenStudy (anonymous):

29

OpenStudy (anonymous):

-29 not 29 :)

OpenStudy (anonymous):

then the result would be -67?

OpenStudy (anonymous):

question. what if the f(x) is -x?

OpenStudy (anonymous):

@PFEH.1999

OpenStudy (anonymous):

-67 ? :| -38 + 29 = - 67 ????

OpenStudy (anonymous):

oh fail

OpenStudy (anonymous):

you're very fast and clever but a little careless :)

OpenStudy (anonymous):

-9 yea

OpenStudy (anonymous):

ok,yes ;)

OpenStudy (anonymous):

you said what? you had another question?

OpenStudy (anonymous):

yea, small question

OpenStudy (anonymous):

what if f(x) was -x

OpenStudy (anonymous):

ok,why "what"? we have this function...here's its graph: |dw:1405537971502:dw|

OpenStudy (anonymous):

so f(-x)=-2x^2-3x+6 is that?

OpenStudy (anonymous):

no...f(-x) = -2x^2+3x+6

OpenStudy (anonymous):

for x^2 both of them would be same as x^2 = (-x)^2 but for -3x it would be +3x as -3(-x) = 3x got it?

OpenStudy (anonymous):

kind of.. so you are just switching the signs

OpenStudy (anonymous):

so it'll end up being -2x^2+3x+6

OpenStudy (anonymous):

instead of the -3

OpenStudy (anonymous):

yes ;)

OpenStudy (anonymous):

any question?

OpenStudy (anonymous):

ok,it seems you don't have any question :D ... bye ;)

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