Question

Need Help Factoring: 12x^2 +7x+1
6x^2-23x+10
x^5-15x^4+26x^3

Answer 1

well here is a method that works all the time...

when you have

\[ax^2 + bx + c = 0\]

for the 1st question

multiply a and c so in the 1st question you have 12* 1 = 12

now find the factors that add to b... so factors of 12 that add to 7..... 3 and 4

then write the solution as

(ax + factor 1)(ax + fractor 2)
---------------------------
a

so you'll have

(12x + 3)(12x + 4)
-----------------
12

remove common factors

3(4x + 1)4(3x + 1)
------------------
12

cancel the common factors and you get

(4x + 1)(3x + 1)

this same method can be applied to question 2.

and question 3 remove a common factor 1st

\[x^3(x^2 - 15x + 26)\]

the quadratic in brackets should be easy to factor

Answer 2

Thanks man i really needed that!