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OpenStudy (anonymous):
Find the x and y intercepts of the line: 5x + 4y = 20.
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OpenStudy (anonymous):
@jdoe0001
OpenStudy (jdoe0001):
well.. as the site says.... set x=0 and then set y= and solve for the other variable
OpenStudy (anonymous):
i still dont know how
OpenStudy (jdoe0001):
well.. you may want to brush up your linear simplification material then
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OpenStudy (jdoe0001):
x-intercept
5x + 4(0) = 20. solve for "x"
y-intercept
5(0) + 4y = 20. solve for "y"
OpenStudy (anonymous):
wait is it (0,5) (4,0)??
OpenStudy (jdoe0001):
hmm well.. what did you get for "x"?
OpenStudy (anonymous):
those are the only ones I got
OpenStudy (jdoe0001):
well.... yeap , those are it
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OpenStudy (anonymous):
x=4
OpenStudy (anonymous):
for the x intercept?
OpenStudy (anonymous):
x int its 4,0
y int is 5,0
OpenStudy (anonymous):
@jdoe0001
OpenStudy (anonymous):
hello? yes??
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OpenStudy (jdoe0001):
\(\bf 5x + 4(0) = 20\implies 5x+0=20\implies 5x=20\implies x=\cfrac{\cancel{ 20 }}{\cancel{ 5 }}
\\ \quad \\
x=4\qquad {\color{brown}{x-intercept\qquad (4,0)}}
\\ \quad \\
5(0)+4y=20\implies 0+4y=20\implies y=\cfrac{\cancel{ 20 }}{\cancel{ 4 }}
\\ \quad \\
y=5\qquad {\color{brown}{ y-intercept\qquad (0,5)}}\)
OpenStudy (anonymous):
ohh ok almost right
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