x-1=√5x-9 solve for x.
after you square on both sides what do you do?
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OpenStudy (mrnood):
\[x-1 = \sqrt{5x}-9\]
OR
\[x-1= \sqrt{5x-9}\]
?
OpenStudy (anonymous):
The square root is over 5x-9
OpenStudy (mrnood):
yes it's right IF the original equation was written like the SECOND option I wrote
i.e. the 9 is inside the sqrt sign
OK
So now expand the left hand side
(x-1)^2=???
OpenStudy (anonymous):
x^2-2x+1
OpenStudy (mrnood):
good
so
x^2-2x+1=5x-9
rearrange so it is ??=0
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OpenStudy (anonymous):
x^2-7x+8=0 ?
OpenStudy (mrnood):
not quite the last term is incorrect
x^2-7x+10=0
Now solve (probably using the quadratic equation formula...)
Remenber there are 2 answers to a quadratic
OpenStudy (anonymous):
okay thank you
OpenStudy (mrnood):
actually - it's easier to solve by factorising...
OpenStudy (anonymous):
That was what I was going to do
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OpenStudy (mrnood):
Not all quadratics factorise - this one does
The formula allows you to solve all solvable quadratics