Question

A line passes through (1, –5) and (–3, 7).Write an equation for the line in point-slope form.
Rewrite the equation in slope-intercept form.

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 1}}\quad ,&{\color{blue}{ 05}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ 7}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values }\\
\qquad \uparrow\\
\textit{point-slope form}\)

and to get it in slope-intercept form , \(\bf y = mx+b\) just solve it for "y"

Answer 2

hmm got a 0 there for no good reason =) anyhow \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 1}}\quad ,&{\color{blue}{ 5}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ 7}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values }\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 3

okay so how would the final answer look