Question

Write an equation for the line that is parallel to the given line and that passes through the given point.

y = 5/4x – 10; (–6, –29) @Hero

Answer 1

i have a way i did it but i wanna know if its right

Answer 2

What have you done so far?

Answer 3

i just plugged the given points where the ten is but then i got stuck

Answer 4

Can you show what you have done more explicitly?

Answer 5

y-5/4x+-6 for the first point

Answer 6

Are you sure you know what you're doing?

Answer 7

the same but with -29 for the second

Answer 8

and no i dont lol thats why im asking for help ;/

Answer 9

1st Observation:
The general form of the equation of a line is y = mx + b

2nd Observation:
The equation of the given line is y = (5/4)x - 10

3rd Observation
Both lines are parallel to each other which means their slopes are the same; therefore, the equation of the line parallel to the given line (so far) is: y = (5/4)x + b


4th Observation
The point (x,y) = (-6,-29) is given, therefore substitute the point into the equation of the parallel line to find b:
-29 = (5/4)(-6) + b

Finish solving for b.

Answer 10

b=−43/2

Answer 11

I get b = -23/2

Double check your work.

Answer 12

When you do, let me know what the equation of the parallel line is.

Answer 13

okay i got it