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Algebra
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2=4^x/2^x
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Notice that \(4^x=(2^2)^x=2^{2x}\).
Solving for x would be helpful
Gotcha.
Still don't get it!
Now you have \(2=\dfrac{2^{2x}}{2^x}\). Remember that \(\dfrac{a^b}{a^c}=a^{b-c}\)?
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Is the answer 1? /:
Yep.
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