Can anyone verify me if my answer is the derivative of .........

Question

anonymous · Answer

$$y'= \frac{ -3x^3 +3x }{ \sqrt{2-x^2} }$$

anonymous · Answer

$$y''= \frac{ 6x^4-24x^2+6 }{ \sqrt{2-x^2} }$$

anonymous · Answer

I took the derivative of the derivative(the second derivative) and ended up with that. I want to make sure I did everything right when I was simplifying to get the second derivative.

anonymous · Answer

$$y''= -9x^2\sqrt{2-x^2}+3\sqrt{2-x^2}-\frac{ 3x^4+3x^2 }{ \sqrt{2-x^2} }$$

anonymous · Answer

that is what I got first before I started simplifying

anonymous · Answer

use Quotient rule

anonymous · Answer

to get the second derivative.

anonymous · Answer

Whatever may be the numerator there should not be any square root in the denominator , using quotient rule

anonymous · Answer

........................................................................... I just noticed. Good bye half hour work. Time to start over -.-'

anonymous · Answer

... I just erased all and I was correct. I just had to bring down the denominator I ate. buh