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OpenStudy (kanwal32):
In quadratic equation ax^2+bx+c=0 ...
(sequence and series)
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OpenStudy (kanwal32):
IN quadratic equation ax^2+bx+c=0. If alpha,beta are the roots of the equation d=b^2-4ac and alpha+beta,alpha^2+beta^2,alpha^3+beta^3 are in GP them
OpenStudy (kanwal32):
A)d is not equal to zero
B)bd=0
C=cd=0
D)d=0
OpenStudy (kanwal32):
@dan815 @ganeshie8 @ikram002p @Miracrown
OpenStudy (kanwal32):
@nincompoop
OpenStudy (kanwal32):
IIT advanced question
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OpenStudy (kanwal32):
@Kainui
ganeshie8 (ganeshie8):
establish below first :
\(\large \alpha + \beta = -\dfrac{b}{a}\)
\(\large \alpha^2 + \beta^2 = \dfrac{b^2}{a^2} - 2\dfrac{c}{a}\)
\(\large \alpha^3 + \beta^3 = -\dfrac{b}{a}\left( \dfrac{b^2}{a^2} - 3\dfrac{c}{a}\right)\)
OpenStudy (kanwal32):
yes
OpenStudy (kanwal32):
i established these
ganeshie8 (ganeshie8):
after that use the geometric mean to get a relation in a,b,c
simplifying it yields \(b^2-4ac = 0\)
or, \(d = 0\)
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OpenStudy (kanwal32):
i got the same answer but the answer is given as cd=0
OpenStudy (kanwal32):
\[does \Delta\] or d makes any difference to u
OpenStudy (kanwal32):
@ganeshie8
ganeshie8 (ganeshie8):
can you take a screenshot and attach if possible - just for clarity
OpenStudy (kanwal32):
OK
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