Hello I need help factoring the top part of this equation. x^2-4x^2

Question

ray_sihota · Answer

attachment

ray_sihota · Answer

Qustion 3 . I can get the bottom factors.

ray_sihota · Answer

I am also having issue with this Qustion 7 as well.

ganeshie8 · Answer

lets work Question 3 first

ganeshie8 · Answer

Question3 :

$$\large \dfrac{x^3-4x^2}{x^3-x^2-12x}$$

ganeshie8 · Answer

start by factoring out the GCF in both numerator and denominator

ganeshie8 · Answer

whats the GCF of numerator ?

ray_sihota · Answer

up top greatest common factor would be x, on the bottom the factors would be (x-4)(x+3)

ganeshie8 · Answer

$$\large \dfrac{x^3-4x^2}{x^3-x^2-12x}$$

$$\large \dfrac{x^2(x-4)}{x(x^2-x-12)}$$

$$\large \dfrac{x(x-4)}{(x-4)(x+3)}$$

ganeshie8 · Answer

(x-4) cancels out in top and bottom giving you :


$$\large \dfrac{x}{x+3}$$

ganeshie8 · Answer

see if that makes more or less sense

ray_sihota · Answer

it makes perfect sense thank you so much

ganeshie8 · Answer

glad to hear :) yw !