Question

Hello I need help factoring the top part of this equation. x^2-4x^2

Answer 1

Qustion 3 . I can get the bottom factors.

Answer 2

I am also having issue with this Qustion 7 as well.

Answer 3

lets work Question 3 first

Answer 4

Question3 :

\[\large \dfrac{x^3-4x^2}{x^3-x^2-12x}\]

Answer 5

start by factoring out the GCF in both numerator and denominator

Answer 6

whats the GCF of numerator ?

Answer 7

up top greatest common factor would be x, on the bottom the factors would be (x-4)(x+3)

Answer 8

\[\large \dfrac{x^3-4x^2}{x^3-x^2-12x}\]

\[\large \dfrac{x^2(x-4)}{x(x^2-x-12)}\]

\[\large \dfrac{x(x-4)}{(x-4)(x+3)}\]

Answer 9

(x-4) cancels out in top and bottom giving you :


\[\large \dfrac{x}{x+3}\]

Answer 10

see if that makes more or less sense

Answer 11

it makes perfect sense thank you so much

Answer 12

glad to hear :) yw !