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What is the radius of (x - 3)2 + (y + 4)2 = 14?
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mathway.com
\[(x-h)^2+(y-k)^2=r^2\] has center \((h,k)\) and radius \(r\) in your case \(r^2=14\)
The general form of the equation for a circle with its center at (h, k) and radius of r is: \[(x-h)^2 +(y-k)^2=r^2\]
r^2=14 r=\[\sqrt{14}\]
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