Question

If F(x) = x + 5 and G(y) = square-root Y , what is the domain of G(F(x))?

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Answer 1

\[\large{G(F(x)) = \sqrt{x+5}}\]

Now, the domain will be the set in which \(\large{\sqrt{x+5}}\) is defined. Any ideas >

Answer 2

i have no idea

Answer 3

sqrt is only defined when the number inside it is 0 or +ve.

Answer 4

So, \[\large{x+5 \ge 0}\]

solving this we get:

\[\large{x \ge -5}\]

So, this is the required domain

Answer 5

so the answer is B?

Answer 6

Yes

Answer 7

thank you! ;)

Answer 8

Your welcome :)