Mathematics
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OpenStudy (rock_mit182):
Solve the compound inequalitie:
0 ≤ 4 + 2x ≤ 22
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OpenStudy (rock_mit182):
i have to substract -4 from both sides, right ?
OpenStudy (zarkon):
you subtract 4 from all 3 pieces
OpenStudy (anonymous):
yes, from all the sides
OpenStudy (rock_mit182):
and then divide by two in all sides ?
OpenStudy (zarkon):
yes
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OpenStudy (anonymous):
correct
OpenStudy (rock_mit182):
\[-4+0\le -4+4+2x \le22-4\]
OpenStudy (anonymous):
yes then combine like terms
OpenStudy (rock_mit182):
\[-4\le2x \le18\]
OpenStudy (anonymous):
yup, then divide by 2
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OpenStudy (rock_mit182):
\[\frac{ -4 }{ 2 }\le \frac{ 2x }{ 2}\le \frac{ 18 }{ 2 }\]
OpenStudy (rock_mit182):
\[-2\le x \le 9\]
OpenStudy (rock_mit182):
when the signs switch?
OpenStudy (anonymous):
the sings switch only when dividing or multiplying by a negative number
OpenStudy (anonymous):
because the 2 is not negative, the sings don't switch
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OpenStudy (anonymous):
so that is the right answer, good job
OpenStudy (rock_mit182):
|dw:1405646371032:dw|
OpenStudy (rock_mit182):
is this the interval notation ?
OpenStudy (anonymous):
correct
OpenStudy (rock_mit182):
what kind of solution is this ?
union,
intersection,
and,
or,
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OpenStudy (rock_mit182):
i guess is a compound inequality...
OpenStudy (rock_mit182):
help me out please !
OpenStudy (anonymous):
im not sure on that part sorry