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Geometry 6 Online
OpenStudy (anonymous):

Need Geometry Help!

OpenStudy (anonymous):

OpenStudy (anonymous):

What is the area of the circle?

OpenStudy (anonymous):

It doesn't say

OpenStudy (anonymous):

You have to figure out the area of the circle. Do you know the formula for area of a circle?

OpenStudy (anonymous):

\[\pi \times \Gamma ^2\]

OpenStudy (anonymous):

pi times radius square correct. So the radius of the circle is what?

OpenStudy (anonymous):

5 units

OpenStudy (anonymous):

So the total area of the circle is what?

OpenStudy (anonymous):

78.5

OpenStudy (anonymous):

Great now we have to subtract out the triangles. Do you know the formula for determining the area of a right triangle?

OpenStudy (anonymous):

it's leg times leg divided by 2

OpenStudy (anonymous):

Very good.

OpenStudy (anonymous):

Now that I have used that formula I have come up with 18 and 4.5

OpenStudy (anonymous):

What do I do next @nelsonjedi ?

OpenStudy (anonymous):

Because If I subtract them I come up with 13.5 and that Is not an answer

OpenStudy (anonymous):

Why would you subtract them from each other? What does the question ask you to solve?

OpenStudy (anonymous):

It asks me to approximate the area of the shaded region. I miss read your reply. Sorry

OpenStudy (anonymous):

No problemo

OpenStudy (anonymous):

So what am I supposed to do?

OpenStudy (anonymous):

|dw:1405652822628:dw| If I know the area of the circle and I know the area of the triangles what would be the area of the shaded areas.(I referenced with (s)

OpenStudy (anonymous):

So would it be 22.5?

OpenStudy (anonymous):

What is the total area of the circle?

OpenStudy (anonymous):

78.5

OpenStudy (anonymous):

And the white triangles take up 22.5 of that area so how much is left shaded

OpenStudy (anonymous):

56 units^2

OpenStudy (anonymous):

Just 56...78.5-22.5=56

OpenStudy (anonymous):

Well in it gives me a list of answers and that's what it says. they are all in units^2

OpenStudy (anonymous):

OK looking at the problem it shows the units as ^2....Great job

OpenStudy (anonymous):

Thank you very much!

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