Medal/Fan A bicycle tire has a diameter of twenty-six inches. If a pebble is stuck in the tire's treads, about how far will the pebble travel with each rotation of the tire? forty point eight two inches eighty-one point six four inches five hundred thirty point six six inches two thousand one hundred twenty-two point six four inches
Im sorry i cant do math with inches but for every rotation of the wheel, the linear distance will be given by 2*pi*r, where r= radius (26 inches)
oh ok thanks for trying ill fan you for trying X)
sorry
its ok i dont understand it either so who am i to judge X)
ok here's the thing, I will draw it so you can understand, ok?
ok thanks XD
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in order for the pebble to hit the ground again, the tire has to go around a full rotation. In order to find out how much area the tire covers in one rotation, we need to know the length around the OUTSIDE of the tire which is the circumference.
i think its the third one
five hundred thirty point six six inches
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It's not the third one, it's the second one. That one decimal place is off because of my rounding. But it is 81.64 not 530.66
ups sorry. On my first answer i said that 26 was the radius but it wasnt. Its the diameter. So its only pi*d = 81.68
oh i get it now you have to multiply the diameter by pie oh my gosh thank you i get it now X)
Its the answer 2 ofc :)
youre welcome!
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