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Simplify the given expression. square root of negative 10 end root times square root of negative 8 negative 4 square root 5 4 square root of 5 4 I square root of 5 negative 4 I square root of 5
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\[\sqrt{-10} * \sqrt{-8}\]
start with\[\sqrt{10}i\times \sqrt{8}i\]
then since \(i^2=-1\) you have \[-\sqrt{80}\] but you still have to write \(\sqrt{80}\) in simplest radical form sort of like the other ones
you got that part?
not really..
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i dont know where to start to write square root of 80 in rad form
you need to find a perfect square inside 80
16 x 5 = 80
just like you wrote \(27=9\times 3\) where \(9\) was the perfect square
got it!
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\[4\sqrt{5}\]
yay! don't forget the minus sign out front
\[-4\sqrt5\]
\[-4\sqrt{5}\] is the answer?
oui
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