Question

What are all the real zeros of y = (x - 12)3 - 10?

Answer 1

@vineeth10

Answer 2

any options?

Answer 3

yes hold up

Answer 4

I looked it up and "real zeros" is where the graph touches the x-axis, meaning y = 0. So to solve this you set y = 0, and then solve for x. I already solved it and got the answer, but try it yourself and see what you get.

Answer 5

y = (x-12)3 - 10
...
y = 3x - 36 - 10
y = 3x - 46
...
3x - 46 = 0

Answer 6

3x = 46
x = 46/3 or 15 1/3

Answer 7

Yes the correct answer is x = 46/3. vineeth10 is correct =)

Answer 8

yep thanks @lamaguineapig

Answer 9

B.x=^3sqrt 10 +12

Answer 10

C.x=^3sqrt-10+12

Answer 11

D.x=^3sqrt 12-10

Answer 12

OH u meany = (x - 12)^3 - 10?

Answer 13

huh?

Answer 14

i mean mean sorry

Answer 15

(x−12)^3−10=0
(x−12)^3=10
(x−12)=^3√10
x=^3√(10)12

Answer 16

x=^3√(10)+12

Answer 17

why not make it easy set the equation to zero

\[(x - 12)^3 - 10 = 0\]

so

\[(x - 12)^3 = 10\]

then

\[x - 12 = \sqrt[3]{10}\]

and you can finish from here

Answer 18

i am right? @campbell_st

Answer 19

looks like it to me...

Answer 20

B is the answer