Question

Solve the following quadratic equation using the square root property: (y + 6)^2 = -4

Only fill in one of the tables.

Answer 1

i give medals

Answer 2

@Venny

Answer 3

@jim_thompson5910

Answer 4

I don't know what "square root property" is but the issue is that if you square root both sides from the beginning you'll get an imaginary number since the square root of -4 is equal to 2i.

The first thing I'd do is distribute (y+6)^2 which turns out to equal (y^2) + 12y + 36 = -4. But I don't know if this is not doing it using the "square root property" way like you are asking.

Answer 5

yea this pellet sucks

Answer 6

pellet lol

Answer 7

ok i guess i can cuss on here sh*it

Answer 8

lol

Answer 9

Hmm I think the answer actually does involve imaginary numbers. When I use my calculator to solve the polynomial y^2 + 12y + 40 it gives me answers, both with imaginary numbers. I get -6-2i and -6+2i

Answer 10

The square root property is the idea where you take the square root of both sides (to undo squaring)

\[\Large (y + 6)^2 = -4\]

\[\Large \sqrt{(y + 6)^2} = \pm \sqrt{-4}\]

\[\Large y+6 = \pm \sqrt{-4}\]

\[\Large y+6 = \pm 2i\]

\[\Large y = 6 \pm 2i\]

\[\Large y = 6 + 2i \ \text{ or } y = 6 - 2i\]

Answer 11

Where \[\Large i = \sqrt{-1}\]

Answer 12

it wont let me put I in because I can only type in so much

Answer 13

You can't put in -6+2i or -6-2i?

Answer 14

no

Answer 15

If you can't put in i, then just leave it as \[\sqrt{-4}\]

Answer 16

So you should get \[-6-\sqrt{-4}\] and \[-6+\sqrt{-4}\]

Answer 17

What's the second thing? I can't read your hand writing. The first one is \[\sqrt{-4}\] but what is the second one?