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anonymous · Answer

@vishweshshrimali5

anonymous · Answer

I just need the procees , i mean what to do

anonymous · Answer

You guide me i will find the answer

vishweshshrimali5 · Answer

Are you sure the product is correct ?

$\color{blue}{\text{Originally Posted by}}$ @No.name
$$5C + 2SO_2 \rightarrow 2BrCl$$
How much CS2 can be produced from 440 kg of wasste SO2 with 60 kg of coke if the SO2 conversion is 80%
$\color{blue}{\text{End of Quote}}$

vishweshshrimali5 · Answer

$$\large{5C + 2SO_2 \rightarrow CS_2 + 4CO}$$

This is probably the correct reaction.

vishweshshrimali5 · Answer

Only 80% of $SO_2$ is going to react, thus, amount of $SO_2$ going to react = 80% of 440 kg --> convert it into moles

Coke = 60 kg --> convert into moles

Now, 5 moles of coke react with 2 moles of $SO_2$ to produce 1 mole of $CS_2$.

Find out the limiting reagent and using that find out the number of moles of $CS_2$ produced.

anonymous · Answer

Sorry about the late reply , my browser crashed
yes my previous reaction , is very much incorrect , sorry about that

anonymous · Answer

GREAT GOT THE ANSWER , THANK YOU SO MUCH

vishweshshrimali5 · Answer

Your welcome :)