Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Lines CD and DE are tangent to circle A as shown below: Lines CD and DE are tangent to circle A and intersect at point D. Arc CE measures 125 degrees. Point B lies on circle A. If arc CE is 125°, what is the measure of ∠CDE? 55° 62.5° 117.5° 125°

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathmale please help me

OpenStudy (anonymous):

PLEASE HELP :)

OpenStudy (mrnood):

do you know that a radius to circle and a tangent are always at right angles?

OpenStudy (anonymous):

yes

OpenStudy (mrnood):

So - you can add 2 right angles to the diagram

OpenStudy (anonymous):

okay.

OpenStudy (mrnood):

|dw:1405780380898:dw|

OpenStudy (mrnood):

the line from the centre bisects the angle at the centre AND the angle CDE

OpenStudy (anonymous):

yes... then what...

OpenStudy (mrnood):

so - what is angle CAD? When you know that - what is angle CDA?

OpenStudy (anonymous):

90?

OpenStudy (mrnood):

I think that was a guess. I said above "the line from the centre bisects the angle at the centre AND the angle CDE" SO CAE = 125, what is CAD?

OpenStudy (anonymous):

It wasn't I promise!! I honestly have no clue.

OpenStudy (anonymous):

I'm sorry... I'm really struggling.

OpenStudy (mrnood):

Just look at the diagram - I really have virtually told you the answer to this part: I said above "the line from the centre bisects the angle at the centre AND the angle CDE" The angle at the centre is CAE = 125 It is bisected |(cut in half) by AD so What is angle CAD?

OpenStudy (anonymous):

62.5

OpenStudy (mrnood):

OK good Now look at the TRIANGLE ACD Which angles do you know? (you know 2 of them..) So what is the third one?

OpenStudy (anonymous):

55

OpenStudy (anonymous):

WAIT NO

OpenStudy (anonymous):

wait ya 55

OpenStudy (mrnood):

|dw:1405781322152:dw| I asked for thtriangle ACD

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!