Lines CD and DE are tangent to circle A as shown below: Lines CD and DE are tangent to circle A and intersect at point D. Arc CE measures 125 degrees. Point B lies on circle A. If arc CE is 125°, what is the measure of ∠CDE? 55° 62.5° 117.5° 125°
@mathmale please help me
PLEASE HELP :)
do you know that a radius to circle and a tangent are always at right angles?
yes
So - you can add 2 right angles to the diagram
okay.
|dw:1405780380898:dw|
the line from the centre bisects the angle at the centre AND the angle CDE
yes... then what...
so - what is angle CAD? When you know that - what is angle CDA?
90?
I think that was a guess. I said above "the line from the centre bisects the angle at the centre AND the angle CDE" SO CAE = 125, what is CAD?
It wasn't I promise!! I honestly have no clue.
I'm sorry... I'm really struggling.
Just look at the diagram - I really have virtually told you the answer to this part: I said above "the line from the centre bisects the angle at the centre AND the angle CDE" The angle at the centre is CAE = 125 It is bisected |(cut in half) by AD so What is angle CAD?
62.5
OK good Now look at the TRIANGLE ACD Which angles do you know? (you know 2 of them..) So what is the third one?
55
WAIT NO
wait ya 55
|dw:1405781322152:dw| I asked for thtriangle ACD
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