How many seven digit numbers are there when 0,8, and 9 can not be the leading number?
seven digit numbers, not counting all 0's would be 1000000 to 9999999
Okay, so is there a formula to figure this one out?
So it's 7? What about different combinations of numbers?
Well I was thinking that like 7894849 could be a number. so thus the answer would be a much larger number, but I might be misunderstanding the question. haha
Starting from 1000000 to 1999999999, there are 999,999 numbers with a lead number of 1 so 7 x 999999 = 6,999,993
999999 lead 1, 999999 lead 2, all the way to lead 7 I misunderstood before
oh, okay. Thanks.
wait
Ok good, I thought I miscounted the number of numbers from 1000000 to 1999999
actually, should it be 7,000,000...because I'm not sure if I counted each starting set (such as 1000000 and 2000000)
I honestly have no idea, I'm pretty confused.
If 0, 8, 9 are excluded...
Then we can start with 1,2,3,4,5,6,7...only.
How many 7-digit numbers can start with 1? @bmo29
starts from 1,000,000 to 1,999,999...
Soo 7,000,000?
You don't seem to be answering my question. Is 7,000,000 for the final answer?
No, is that how many can start with 1?
Starting with 1, the smallest number is 1,000,000, and the largest number is 1,999,999. How many numbers are there?
If that sounds complicated, how many numbers are there from 10 to 19?
9
10,11,12,13,14,15,16,17,18,19 There are 10 numbers. What you need to do is to subtract 10 from 19 but ADD 1 because both the first and last counts. ok so far?
Yes, so 10
So how many numbers from 1,000,000 to1,999,999?
In fact, we can do it in one single step, how many numbers from 1,000,000 to 7,999,999?
7,000,000
That's the answer to your problem! Well done!
oh, wow! Thanks!
You're welcome! :)
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